Base | Representation |
---|---|
bin | 100000001001000001… |
… | …111011101101101111 |
3 | 10022002010222122022211 |
4 | 200021001323231233 |
5 | 1031134334140142 |
6 | 23504303351251 |
7 | 2331135462124 |
oct | 401101735557 |
9 | 108063878284 |
10 | 34511240047 |
11 | 136aa771499 |
12 | 68318b2527 |
13 | 333cba59cb |
14 | 195563c74b |
15 | d6ebd7917 |
hex | 80907bb6f |
34511240047 has 2 divisors, whose sum is σ = 34511240048. Its totient is φ = 34511240046.
The previous prime is 34511240039. The next prime is 34511240131. The reversal of 34511240047 is 74004211543.
34511240047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (74004211543) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34511240047 - 23 = 34511240039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34511240347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17255620023 + 17255620024.
It is an arithmetic number, because the mean of its divisors is an integer number (17255620024).
Almost surely, 234511240047 is an apocalyptic number.
34511240047 is a deficient number, since it is larger than the sum of its proper divisors (1).
34511240047 is an equidigital number, since it uses as much as digits as its factorization.
34511240047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
The spelling of 34511240047 in words is "thirty-four billion, five hundred eleven million, two hundred forty thousand, forty-seven".
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