34513001641453 has 4 divisors (see below), whose sum is σ = 34515076629628. Its totient is φ = 34510926653280.

The previous prime is 34513001641451. The next prime is 34513001641471. The reversal of 34513001641453 is 35414610031543.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2088666629284 + 32424335012169 = 1445222^2 + 5694237^2 .

It is a cyclic number.

It is not a de Polignac number, because 34513001641453 - 2¹ = 34513001641451 is a prime.

It is a super-3 number, since 3×34513001641453³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34513001641451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1037469138 + ... + 1037502403.

It is an arithmetic number, because the mean of its divisors is an integer number (8628769157407).

Almost surely, 2^{34513001641453} is an apocalyptic number.

It is an amenable number.

34513001641453 is a deficient number, since it is larger than the sum of its proper divisors (2074988175).

34513001641453 is a wasteful number, since it uses less digits than its factorization.

34513001641453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2074988174.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 34513001641453 its reverse (35414610031543), we get a palindrome (69927611672996).

The spelling of 34513001641453 in words is "thirty-four trillion, five hundred thirteen billion, one million, six hundred forty-one thousand, four hundred fifty-three".