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34513440042 = 2320692780203
BaseRepresentation
bin100000001001001010…
…010100110100101010
310022002022010102011010
4200021022110310222
51031140420040132
623504422444350
72331163254114
oct401112246452
9108068112133
1034513440042
1113700a34374
1268325936b6
133340496193
141955a523b4
15d6eebe6cc
hex809294d2a

34513440042 has 16 divisors (see below), whose sum is σ = 69060267360. Its totient is φ = 11498915472.

The previous prime is 34513439999. The next prime is 34513440053. The reversal of 34513440042 is 24004431543.

It is a super-3 number, since 3×345134400423 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34513439991 and 34513440009.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1377688 + ... + 1402515.

It is an arithmetic number, because the mean of its divisors is an integer number (4316266710).

Almost surely, 234513440042 is an apocalyptic number.

34513440042 is an abundant number, since it is smaller than the sum of its proper divisors (34546827318).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

34513440042 is a wasteful number, since it uses less digits than its factorization.

34513440042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2782277.

The product of its (nonzero) digits is 23040, while the sum is 30.

Adding to 34513440042 its reverse (24004431543), we get a palindrome (58517871585).

The spelling of 34513440042 in words is "thirty-four billion, five hundred thirteen million, four hundred forty thousand, forty-two".

Divisors: 1 2 3 6 2069 4138 6207 12414 2780203 5560406 8340609 16681218 5752240007 11504480014 17256720021 34513440042