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345150005131 is a prime number
BaseRepresentation
bin1010000010111001000…
…10110001111110001011
31012222220002121221011101
411001130202301332023
521123331400131011
6422320522242231
733636065431351
oct5013442617613
91188802557141
10345150005131
111234171a8428
1256a86056377
1326716b41089
14129c369b7d1
158ea137d2c1
hex505c8b1f8b

345150005131 has 2 divisors, whose sum is σ = 345150005132. Its totient is φ = 345150005130.

The previous prime is 345150005099. The next prime is 345150005147. The reversal of 345150005131 is 131500051543.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 345150005131 - 25 = 345150005099 is a prime.

It is a super-2 number, since 2×3451500051312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 345150005131.

It is not a weakly prime, because it can be changed into another prime (345150005171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172575002565 + 172575002566.

It is an arithmetic number, because the mean of its divisors is an integer number (172575002566).

Almost surely, 2345150005131 is an apocalyptic number.

345150005131 is a deficient number, since it is larger than the sum of its proper divisors (1).

345150005131 is an equidigital number, since it uses as much as digits as its factorization.

345150005131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 345150005131 its reverse (131500051543), we get a palindrome (476650056674).

The spelling of 345150005131 in words is "three hundred forty-five billion, one hundred fifty million, five thousand, one hundred thirty-one".