Base | Representation |
---|---|
bin | 1010000011000110010… |
… | …11011100000011010111 |
3 | 1020000011212002122102221 |
4 | 11001203023130003113 |
5 | 21124043344422201 |
6 | 422335540243211 |
7 | 33641616565531 |
oct | 5014313340327 |
9 | 1200155078387 |
10 | 345261326551 |
11 | 1234740218a9 |
12 | 56ab73a0507 |
13 | 26733c19a3b |
14 | 129d4398851 |
15 | 8eab01c4a1 |
hex | 50632dc0d7 |
345261326551 has 2 divisors, whose sum is σ = 345261326552. Its totient is φ = 345261326550.
The previous prime is 345261326513. The next prime is 345261326587. The reversal of 345261326551 is 155623162543.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 345261326551 - 211 = 345261324503 is a prime.
It is a super-2 number, since 2×3452613265512 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 345261326498 and 345261326507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (345261926551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172630663275 + 172630663276.
It is an arithmetic number, because the mean of its divisors is an integer number (172630663276).
Almost surely, 2345261326551 is an apocalyptic number.
345261326551 is a deficient number, since it is larger than the sum of its proper divisors (1).
345261326551 is an equidigital number, since it uses as much as digits as its factorization.
345261326551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648000, while the sum is 43.
The spelling of 345261326551 in words is "three hundred forty-five billion, two hundred sixty-one million, three hundred twenty-six thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •