Base | Representation |
---|---|
bin | 1111101101000101100010… |
… | …10010010000101111100011 |
3 | 11112021110121110220122221022 |
4 | 13312202301102100233203 |
5 | 14011303134410223433 |
6 | 201240534023520055 |
7 | 10163015246431031 |
oct | 766426122205743 |
9 | 145243543818838 |
10 | 34534511414243 |
11 | 10005005420475 |
12 | 3a59029bb902b |
13 | 163678a2bc809 |
14 | 87569d195551 |
15 | 3ed4c65d6698 |
hex | 1f68b1490be3 |
34534511414243 has 2 divisors, whose sum is σ = 34534511414244. Its totient is φ = 34534511414242.
The previous prime is 34534511414177. The next prime is 34534511414257. The reversal of 34534511414243 is 34241411543543.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34534511414243 - 210 = 34534511413219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34534511414194 and 34534511414203.
It is not a weakly prime, because it can be changed into another prime (34534511416243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17267255707121 + 17267255707122.
It is an arithmetic number, because the mean of its divisors is an integer number (17267255707122).
Almost surely, 234534511414243 is an apocalyptic number.
34534511414243 is a deficient number, since it is larger than the sum of its proper divisors (1).
34534511414243 is an equidigital number, since it uses as much as digits as its factorization.
34534511414243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1382400, while the sum is 44.
Adding to 34534511414243 its reverse (34241411543543), we get a palindrome (68775922957786).
The spelling of 34534511414243 in words is "thirty-four trillion, five hundred thirty-four billion, five hundred eleven million, four hundred fourteen thousand, two hundred forty-three".
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