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3453553563143 is a prime number
BaseRepresentation
bin110010010000010111110…
…101010101011000000111
3110020011020002022112021112
4302100113311111120013
5423040334203010033
611202312434235235
7504340163635205
oct62202765253007
913204202275245
103453553563143
111111709a52772
124793a4125b1b
131c08901ac738
14bd21d72c075
155ec7c96ec48
hex32417d55607

3453553563143 has 2 divisors, whose sum is σ = 3453553563144. Its totient is φ = 3453553563142.

The previous prime is 3453553563137. The next prime is 3453553563179. The reversal of 3453553563143 is 3413653553543.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3453553563143 - 24 = 3453553563127 is a prime.

It is a super-2 number, since 2×34535535631432 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3453553563091 and 3453553563100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3453553553143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1726776781571 + 1726776781572.

It is an arithmetic number, because the mean of its divisors is an integer number (1726776781572).

Almost surely, 23453553563143 is an apocalyptic number.

3453553563143 is a deficient number, since it is larger than the sum of its proper divisors (1).

3453553563143 is an equidigital number, since it uses as much as digits as its factorization.

3453553563143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14580000, while the sum is 50.

The spelling of 3453553563143 in words is "three trillion, four hundred fifty-three billion, five hundred fifty-three million, five hundred sixty-three thousand, one hundred forty-three".