345452413441 has 4 divisors (see below), whose sum is σ = 346112934832. Its totient is φ = 344791892052.

The previous prime is 345452413433. The next prime is 345452413507. The reversal of 345452413441 is 144314254543.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 345452413441 - 2³ = 345452413433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 345452413394 and 345452413403.

It is not an unprimeable number, because it can be changed into a prime (345452414441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 330259911 + ... + 330260956.

It is an arithmetic number, because the mean of its divisors is an integer number (86528233708).

Almost surely, 2^345452413441 is an apocalyptic number.

It is an amenable number.

345452413441 is a deficient number, since it is larger than the sum of its proper divisors (660521391).

345452413441 is an equidigital number, since it uses as much as digits as its factorization.

345452413441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 660521390.

The product of its digits is 460800, while the sum is 40.

Adding to 345452413441 its reverse (144314254543), we get a palindrome (489766667984).

The spelling of 345452413441 in words is "three hundred forty-five billion, four hundred fifty-two million, four hundred thirteen thousand, four hundred forty-one".