Base | Representation |
---|---|
bin | 1111101101011010000101… |
… | …01010100011001011001111 |
3 | 11112022112002002220210202211 |
4 | 13312231002222203023033 |
5 | 14011443231321141421 |
6 | 201250000245331251 |
7 | 10163555460366541 |
oct | 766550252431317 |
9 | 145275062823684 |
10 | 34545540412111 |
11 | 10009754a64843 |
12 | 3a5b1a7706b27 |
13 | 163782722ac61 |
14 | 876027c53691 |
15 | 3ed91e9a29e1 |
hex | 1f6b42aa32cf |
34545540412111 has 4 divisors (see below), whose sum is σ = 34545590923824. Its totient is φ = 34545489900400.
The previous prime is 34545540412099. The next prime is 34545540412133. The reversal of 34545540412111 is 11121404554543.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34545540412111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34545540412181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24215710 + ... + 25602571.
It is an arithmetic number, because the mean of its divisors is an integer number (8636397730956).
Almost surely, 234545540412111 is an apocalyptic number.
34545540412111 is a deficient number, since it is larger than the sum of its proper divisors (50511713).
34545540412111 is an equidigital number, since it uses as much as digits as its factorization.
34545540412111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50511712.
The product of its (nonzero) digits is 192000, while the sum is 40.
Adding to 34545540412111 its reverse (11121404554543), we get a palindrome (45666944966654).
The spelling of 34545540412111 in words is "thirty-four trillion, five hundred forty-five billion, five hundred forty million, four hundred twelve thousand, one hundred eleven".
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