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3454632513217 is a prime number
BaseRepresentation
bin110010010001011000001…
…001001100111011000001
3110020021000021112212112101
4302101120021030323001
5423100041410410332
611203011500030401
7504406004600224
oct62213011147301
913207007485471
103454632513217
111112112a9a946
12479645532401
131c0a028a0132
14bd2c2b4b5bb
155ece2548ae7
hex3245824cec1

3454632513217 has 2 divisors, whose sum is σ = 3454632513218. Its totient is φ = 3454632513216.

The previous prime is 3454632513187. The next prime is 3454632513287. The reversal of 3454632513217 is 7123152364543.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3451275933121 + 3356580096 = 1857761^2 + 57936^2 .

It is an emirp because it is prime and its reverse (7123152364543) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3454632513217 is a prime.

It is not a weakly prime, because it can be changed into another prime (3454632513287) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1727316256608 + 1727316256609.

It is an arithmetic number, because the mean of its divisors is an integer number (1727316256609).

Almost surely, 23454632513217 is an apocalyptic number.

It is an amenable number.

3454632513217 is a deficient number, since it is larger than the sum of its proper divisors (1).

3454632513217 is an equidigital number, since it uses as much as digits as its factorization.

3454632513217 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1814400, while the sum is 46.

The spelling of 3454632513217 in words is "three trillion, four hundred fifty-four billion, six hundred thirty-two million, five hundred thirteen thousand, two hundred seventeen".