Base | Representation |
---|---|
bin | 100111010001110111000011… |
… | …0000110110101110100111011 |
3 | 1200022022200211121211111021202 |
4 | 1032203232012012311310323 |
5 | 330241202204324214121 |
6 | 3222453322313524415 |
7 | 132526501116140546 |
oct | 11643560606656473 |
9 | 1608280747744252 |
10 | 345502304132411 |
11 | a00a6782502308 |
12 | 329007b271370b |
13 | 11aa295c37265a |
14 | 614658790385d |
15 | 29e2493d1b40b |
hex | 13a3b861b5d3b |
345502304132411 has 2 divisors, whose sum is σ = 345502304132412. Its totient is φ = 345502304132410.
The previous prime is 345502304132393. The next prime is 345502304132413. The reversal of 345502304132411 is 114231403205543.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 345502304132411 - 26 = 345502304132347 is a prime.
Together with 345502304132413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (345502304132413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172751152066205 + 172751152066206.
It is an arithmetic number, because the mean of its divisors is an integer number (172751152066206).
Almost surely, 2345502304132411 is an apocalyptic number.
345502304132411 is a deficient number, since it is larger than the sum of its proper divisors (1).
345502304132411 is an equidigital number, since it uses as much as digits as its factorization.
345502304132411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 345502304132411 its reverse (114231403205543), we get a palindrome (459733707337954).
The spelling of 345502304132411 in words is "three hundred forty-five trillion, five hundred two billion, three hundred four million, one hundred thirty-two thousand, four hundred eleven".
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