Base | Representation |
---|---|
bin | 1111101101101010100111… |
… | …00110001000100111111111 |
3 | 11112100100222112220012110202 |
4 | 13312311103212020213333 |
5 | 14012114420041331142 |
6 | 201254025005554115 |
7 | 10164321413145401 |
oct | 766652346104777 |
9 | 145310875805422 |
10 | 34554414402047 |
11 | 10012499109821 |
12 | 3a60a6357593b |
13 | 163860c85b887 |
14 | 87662a626b71 |
15 | 3edc8da8d032 |
hex | 1f6d539889ff |
34554414402047 has 2 divisors, whose sum is σ = 34554414402048. Its totient is φ = 34554414402046.
The previous prime is 34554414402037. The next prime is 34554414402083. The reversal of 34554414402047 is 74020441445543.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34554414402047 - 214 = 34554414385663 is a prime.
It is a super-3 number, since 3×345544144020473 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34554414401992 and 34554414402010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34554414402037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17277207201023 + 17277207201024.
It is an arithmetic number, because the mean of its divisors is an integer number (17277207201024).
Almost surely, 234554414402047 is an apocalyptic number.
34554414402047 is a deficient number, since it is larger than the sum of its proper divisors (1).
34554414402047 is an equidigital number, since it uses as much as digits as its factorization.
34554414402047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4300800, while the sum is 47.
The spelling of 34554414402047 in words is "thirty-four trillion, five hundred fifty-four billion, four hundred fourteen million, four hundred two thousand, forty-seven".
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