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34554414402047 is a prime number
BaseRepresentation
bin1111101101101010100111…
…00110001000100111111111
311112100100222112220012110202
413312311103212020213333
514012114420041331142
6201254025005554115
710164321413145401
oct766652346104777
9145310875805422
1034554414402047
1110012499109821
123a60a6357593b
13163860c85b887
1487662a626b71
153edc8da8d032
hex1f6d539889ff

34554414402047 has 2 divisors, whose sum is σ = 34554414402048. Its totient is φ = 34554414402046.

The previous prime is 34554414402037. The next prime is 34554414402083. The reversal of 34554414402047 is 74020441445543.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 34554414402047 - 214 = 34554414385663 is a prime.

It is a super-3 number, since 3×345544144020473 (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34554414401992 and 34554414402010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34554414402037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17277207201023 + 17277207201024.

It is an arithmetic number, because the mean of its divisors is an integer number (17277207201024).

Almost surely, 234554414402047 is an apocalyptic number.

34554414402047 is a deficient number, since it is larger than the sum of its proper divisors (1).

34554414402047 is an equidigital number, since it uses as much as digits as its factorization.

34554414402047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4300800, while the sum is 47.

The spelling of 34554414402047 in words is "thirty-four trillion, five hundred fifty-four billion, four hundred fourteen million, four hundred two thousand, forty-seven".