Base | Representation |
---|---|
bin | 1111101101101010100111… |
… | …00110001000101000000011 |
3 | 11112100100222112220012110220 |
4 | 13312311103212020220003 |
5 | 14012114420041331201 |
6 | 201254025005554123 |
7 | 10164321413145405 |
oct | 766652346105003 |
9 | 145310875805426 |
10 | 34554414402051 |
11 | 10012499109825 |
12 | 3a60a63575943 |
13 | 163860c85b88b |
14 | 87662a626b75 |
15 | 3edc8da8d036 |
hex | 1f6d53988a03 |
34554414402051 has 4 divisors (see below), whose sum is σ = 46072552536072. Its totient is φ = 23036276268032.
The previous prime is 34554414402047. The next prime is 34554414402083. The reversal of 34554414402051 is 15020441445543.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34554414402051 - 22 = 34554414402047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34554414401994 and 34554414402012.
It is not an unprimeable number, because it can be changed into a prime (34554414402091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5759069067006 + ... + 5759069067011.
It is an arithmetic number, because the mean of its divisors is an integer number (11518138134018).
Almost surely, 234554414402051 is an apocalyptic number.
34554414402051 is a deficient number, since it is larger than the sum of its proper divisors (11518138134021).
34554414402051 is a wasteful number, since it uses less digits than its factorization.
34554414402051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11518138134020.
The product of its (nonzero) digits is 768000, while the sum is 42.
Adding to 34554414402051 its reverse (15020441445543), we get a palindrome (49574855847594).
The spelling of 34554414402051 in words is "thirty-four trillion, five hundred fifty-four billion, four hundred fourteen million, four hundred two thousand, fifty-one".
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