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34554414402051 = 311518138134017
BaseRepresentation
bin1111101101101010100111…
…00110001000101000000011
311112100100222112220012110220
413312311103212020220003
514012114420041331201
6201254025005554123
710164321413145405
oct766652346105003
9145310875805426
1034554414402051
1110012499109825
123a60a63575943
13163860c85b88b
1487662a626b75
153edc8da8d036
hex1f6d53988a03

34554414402051 has 4 divisors (see below), whose sum is σ = 46072552536072. Its totient is φ = 23036276268032.

The previous prime is 34554414402047. The next prime is 34554414402083. The reversal of 34554414402051 is 15020441445543.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34554414402051 - 22 = 34554414402047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34554414401994 and 34554414402012.

It is not an unprimeable number, because it can be changed into a prime (34554414402091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5759069067006 + ... + 5759069067011.

It is an arithmetic number, because the mean of its divisors is an integer number (11518138134018).

Almost surely, 234554414402051 is an apocalyptic number.

34554414402051 is a deficient number, since it is larger than the sum of its proper divisors (11518138134021).

34554414402051 is a wasteful number, since it uses less digits than its factorization.

34554414402051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11518138134020.

The product of its (nonzero) digits is 768000, while the sum is 42.

Adding to 34554414402051 its reverse (15020441445543), we get a palindrome (49574855847594).

The spelling of 34554414402051 in words is "thirty-four trillion, five hundred fifty-four billion, four hundred fourteen million, four hundred two thousand, fifty-one".

Divisors: 1 3 11518138134017 34554414402051