Base | Representation |
---|---|
bin | 110010100001110010001… |
… | …110100101001010100011 |
3 | 110021221111001221221010011 |
4 | 302201302032211022203 |
5 | 423342132000000120 |
6 | 11215043555545351 |
7 | 505601410011445 |
oct | 62416216451243 |
9 | 13257431857104 |
10 | 3472250000035 |
11 | 1119633670503 |
12 | 480b415bb257 |
13 | 1c257c7a264b |
14 | c00b4846495 |
15 | 604c4044c5a |
hex | 328723a52a3 |
3472250000035 has 8 divisors (see below), whose sum is σ = 4166929894320. Its totient is φ = 2777646737184.
The previous prime is 3472250000003. The next prime is 3472250000059. The reversal of 3472250000035 is 5300000522743.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3472250000035 - 25 = 3472250000003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3472249999961 and 3472250000006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19058125 + ... + 19239454.
It is an arithmetic number, because the mean of its divisors is an integer number (520866236790).
Almost surely, 23472250000035 is an apocalyptic number.
3472250000035 is a deficient number, since it is larger than the sum of its proper divisors (694679894285).
3472250000035 is a wasteful number, since it uses less digits than its factorization.
3472250000035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38315717.
The product of its (nonzero) digits is 25200, while the sum is 31.
Adding to 3472250000035 its reverse (5300000522743), we get a palindrome (8772250522778).
The spelling of 3472250000035 in words is "three trillion, four hundred seventy-two billion, two hundred fifty million, thirty-five", and thus it is an aban number.
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