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3480674008373 is a prime number
BaseRepresentation
bin110010101001101000010…
…101100111110100110101
3110022202020011012220002222
4302221220111213310311
5424011410021231443
611222555523412125
7506320226625512
oct62515025476465
913282204186088
103480674008373
111122166811671
124826b2824045
131c32c2b11a73
14c0673564309
1560818897468
hex32a68567d35

3480674008373 has 2 divisors, whose sum is σ = 3480674008374. Its totient is φ = 3480674008372.

The previous prime is 3480674008349. The next prime is 3480674008381. The reversal of 3480674008373 is 3738004760843.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1744243207204 + 1736430801169 = 1320698^2 + 1317737^2 .

It is an emirp because it is prime and its reverse (3738004760843) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3480674008373 - 232 = 3476379041077 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3480674008313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740337004186 + 1740337004187.

It is an arithmetic number, because the mean of its divisors is an integer number (1740337004187).

Almost surely, 23480674008373 is an apocalyptic number.

It is an amenable number.

3480674008373 is a deficient number, since it is larger than the sum of its proper divisors (1).

3480674008373 is an equidigital number, since it uses as much as digits as its factorization.

3480674008373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8128512, while the sum is 53.

The spelling of 3480674008373 in words is "three trillion, four hundred eighty billion, six hundred seventy-four million, eight thousand, three hundred seventy-three".