Base | Representation |
---|---|
bin | 110010101001101000010… |
… | …110001000111001000101 |
3 | 110022202020011110202220021 |
4 | 302221220112020321011 |
5 | 424011410040100223 |
6 | 11222555530335141 |
7 | 506320231031416 |
oct | 62515026107105 |
9 | 13282204422807 |
10 | 3480674143813 |
11 | 11221668a43a9 |
12 | 4826b288a4b1 |
13 | 1c32c2b5b5c9 |
14 | c067359b80d |
15 | 608188c265d |
hex | 32a68588e45 |
3480674143813 has 2 divisors, whose sum is σ = 3480674143814. Its totient is φ = 3480674143812.
The previous prime is 3480674143781. The next prime is 3480674143823. The reversal of 3480674143813 is 3183414760843.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3456617203204 + 24056940609 = 1859198^2 + 155103^2 .
It is a cyclic number.
It is not a de Polignac number, because 3480674143813 - 25 = 3480674143781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3480674143823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740337071906 + 1740337071907.
It is an arithmetic number, because the mean of its divisors is an integer number (1740337071907).
Almost surely, 23480674143813 is an apocalyptic number.
It is an amenable number.
3480674143813 is a deficient number, since it is larger than the sum of its proper divisors (1).
3480674143813 is an equidigital number, since it uses as much as digits as its factorization.
3480674143813 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4644864, while the sum is 52.
The spelling of 3480674143813 in words is "three trillion, four hundred eighty billion, six hundred seventy-four million, one hundred forty-three thousand, eight hundred thirteen".
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