Base | Representation |
---|---|
bin | 110010101001111100100… |
… | …011010100111100101111 |
3 | 110022210002210100211122021 |
4 | 302221330203110330233 |
5 | 424013103331123031 |
6 | 11223053320331011 |
7 | 506331515350255 |
oct | 62517443247457 |
9 | 13283083324567 |
10 | 3481013145391 |
11 | 11223201972a1 |
12 | 482788313a67 |
13 | 1c3348163662 |
14 | c06a66045d5 |
15 | 60838537511 |
hex | 32a7c8d4f2f |
3481013145391 has 2 divisors, whose sum is σ = 3481013145392. Its totient is φ = 3481013145390.
The previous prime is 3481013145359. The next prime is 3481013145403. The reversal of 3481013145391 is 1935413101843.
3481013145391 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3481013145391 - 25 = 3481013145359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3481013145331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740506572695 + 1740506572696.
It is an arithmetic number, because the mean of its divisors is an integer number (1740506572696).
Almost surely, 23481013145391 is an apocalyptic number.
3481013145391 is a deficient number, since it is larger than the sum of its proper divisors (1).
3481013145391 is an equidigital number, since it uses as much as digits as its factorization.
3481013145391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 43.
The spelling of 3481013145391 in words is "three trillion, four hundred eighty-one billion, thirteen million, one hundred forty-five thousand, three hundred ninety-one".
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