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3483079315213 is a prime number
BaseRepresentation
bin110010101011110111101…
…101001000111100001101
3110022222102210020010210111
4302223313231020330031
5424031321301041323
611224034325440021
7506433644454061
oct62536755107415
913288383203714
103483079315213
111123190519263
12483064270011
131c35b7238054
14c0820ba5aa1
1560909b1ac0d
hex32af7b48f0d

3483079315213 has 2 divisors, whose sum is σ = 3483079315214. Its totient is φ = 3483079315212.

The previous prime is 3483079315151. The next prime is 3483079315223. The reversal of 3483079315213 is 3125139703843.

3483079315213 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3480978284644 + 2101030569 = 1865738^2 + 45837^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3483079315213 is a prime.

It is a super-2 number, since 2×34830793152132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3483079315223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1741539657606 + 1741539657607.

It is an arithmetic number, because the mean of its divisors is an integer number (1741539657607).

Almost surely, 23483079315213 is an apocalyptic number.

It is an amenable number.

3483079315213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3483079315213 is an equidigital number, since it uses as much as digits as its factorization.

3483079315213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 49.

The spelling of 3483079315213 in words is "three trillion, four hundred eighty-three billion, seventy-nine million, three hundred fifteen thousand, two hundred thirteen".