3483141451781 has 2 divisors, whose sum is σ = 3483141451782. Its totient is φ = 3483141451780.

The previous prime is 3483141451759. The next prime is 3483141451813. The reversal of 3483141451781 is 1871541413843.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1953551313025 + 1529590138756 = 1397695^2 + 1236766^2 .

It is an emirp because it is prime and its reverse (1871541413843) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3483141451781 - 2¹⁰ = 3483141450757 is a prime.

It is a super-3 number, since 3×3483141451781³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3483141459781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1741570725890 + 1741570725891.

It is an arithmetic number, because the mean of its divisors is an integer number (1741570725891).

Almost surely, 2^{3483141451781} is an apocalyptic number.

It is an amenable number.

3483141451781 is a deficient number, since it is larger than the sum of its proper divisors (1).

3483141451781 is an equidigital number, since it uses as much as digits as its factorization.

3483141451781 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1290240, while the sum is 50.

The spelling of 3483141451781 in words is "three trillion, four hundred eighty-three billion, one hundred forty-one million, four hundred fifty-one thousand, seven hundred eighty-one".