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34880111953 is a prime number
BaseRepresentation
bin100000011111000001…
…000100010101010001
310100000212002021110021
4200133001010111101
51032413302040303
624005041503441
72343235026331
oct403701042521
9110025067407
1034880111953
1113879a06405
126915341b81
13339b4389cb
14198c61d0c1
15d9229cebd
hex81f044551

34880111953 has 2 divisors, whose sum is σ = 34880111954. Its totient is φ = 34880111952.

The previous prime is 34880111921. The next prime is 34880111963. The reversal of 34880111953 is 35911108843.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20395267344 + 14484844609 = 142812^2 + 120353^2 .

It is an emirp because it is prime and its reverse (35911108843) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34880111953 - 25 = 34880111921 is a prime.

It is not a weakly prime, because it can be changed into another prime (34880111963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17440055976 + 17440055977.

It is an arithmetic number, because the mean of its divisors is an integer number (17440055977).

Almost surely, 234880111953 is an apocalyptic number.

It is an amenable number.

34880111953 is a deficient number, since it is larger than the sum of its proper divisors (1).

34880111953 is an equidigital number, since it uses as much as digits as its factorization.

34880111953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 43.

The spelling of 34880111953 in words is "thirty-four billion, eight hundred eighty million, one hundred eleven thousand, nine hundred fifty-three".