Search a number
-
+
3490210101011 = 34841100175371
BaseRepresentation
bin110010110010100000101…
…110111011011100010011
3110100122211202001120222012
4302302200232323130103
5424140422241213021
611231214055133135
7510105442236044
oct62624056733423
913318752046865
103490210101011
11112620a681167
124845143741ab
131c418267332a
14c0cd9c488cb
1560bc5b6b35b
hex32ca0bbb713

3490210101011 has 4 divisors (see below), whose sum is σ = 3490310311224. Its totient is φ = 3490109890800.

The previous prime is 3490210100933. The next prime is 3490210101019. The reversal of 3490210101011 is 1101010120943.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3490210101011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3490210101019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50052845 + ... + 50122526.

It is an arithmetic number, because the mean of its divisors is an integer number (872577577806).

Almost surely, 23490210101011 is an apocalyptic number.

3490210101011 is a deficient number, since it is larger than the sum of its proper divisors (100210213).

3490210101011 is a wasteful number, since it uses less digits than its factorization.

3490210101011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100210212.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 3490210101011 its reverse (1101010120943), we get a palindrome (4591220221954).

The spelling of 3490210101011 in words is "three trillion, four hundred ninety billion, two hundred ten million, one hundred one thousand, eleven".

Divisors: 1 34841 100175371 3490210101011