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349034388953 is a prime number
BaseRepresentation
bin1010001010001000001…
…00100001110111011001
31020100220210210002000212
411011010010201313121
521204310300421303
6424202202140505
734134253232465
oct5050404416731
91210823702025
10349034388953
1112502a8a4498
125778aab1735
1326bb5812043
1412c715174a5
15912c3b6ad8
hex5144121dd9

349034388953 has 2 divisors, whose sum is σ = 349034388954. Its totient is φ = 349034388952.

The previous prime is 349034388881. The next prime is 349034388973. The reversal of 349034388953 is 359883430943.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 233456147929 + 115578241024 = 483173^2 + 339968^2 .

It is an emirp because it is prime and its reverse (359883430943) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 349034388953 - 28 = 349034388697 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 349034388892 and 349034388901.

It is not a weakly prime, because it can be changed into another prime (349034388973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174517194476 + 174517194477.

It is an arithmetic number, because the mean of its divisors is an integer number (174517194477).

Almost surely, 2349034388953 is an apocalyptic number.

It is an amenable number.

349034388953 is a deficient number, since it is larger than the sum of its proper divisors (1).

349034388953 is an equidigital number, since it uses as much as digits as its factorization.

349034388953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33592320, while the sum is 59.

The spelling of 349034388953 in words is "three hundred forty-nine billion, thirty-four million, three hundred eighty-eight thousand, nine hundred fifty-three".