Base | Representation |
---|---|
bin | 1111111000000100000110… |
… | …01111011110001110110101 |
3 | 11120121112012010100121100011 |
4 | 13330002003033132032311 |
5 | 14033443123142200143 |
6 | 202130113423420221 |
7 | 10232200242111262 |
oct | 774020317361665 |
9 | 146545163317304 |
10 | 34911696053173 |
11 | 1013aa70304365 |
12 | 3aba154454671 |
13 | 166320aba81b4 |
14 | 889a411b0269 |
15 | 4081eeee2e9d |
hex | 1fc0833de3b5 |
34911696053173 has 2 divisors, whose sum is σ = 34911696053174. Its totient is φ = 34911696053172.
The previous prime is 34911696053147. The next prime is 34911696053207. The reversal of 34911696053173 is 37135069611943.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24834106124689 + 10077589928484 = 4983383^2 + 3174522^2 .
It is a cyclic number.
It is not a de Polignac number, because 34911696053173 - 233 = 34903106118581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34911696063173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17455848026586 + 17455848026587.
It is an arithmetic number, because the mean of its divisors is an integer number (17455848026587).
Almost surely, 234911696053173 is an apocalyptic number.
It is an amenable number.
34911696053173 is a deficient number, since it is larger than the sum of its proper divisors (1).
34911696053173 is an equidigital number, since it uses as much as digits as its factorization.
34911696053173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11022480, while the sum is 58.
The spelling of 34911696053173 in words is "thirty-four trillion, nine hundred eleven billion, six hundred ninety-six million, fifty-three thousand, one hundred seventy-three".
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