Base | Representation |
---|---|
bin | 1111111000000100110110… |
… | …11001000011111010101101 |
3 | 11120121120020100202012202102 |
4 | 13330002123121003322231 |
5 | 14033444440403020023 |
6 | 202130221535504445 |
7 | 10232213262012563 |
oct | 774023331037255 |
9 | 146546210665672 |
10 | 34912101220013 |
11 | 10140158a89196 |
12 | 3aba248088125 |
13 | 1663273b084a4 |
14 | 889a7cd1ba33 |
15 | 408225877628 |
hex | 1fc09b643ead |
34912101220013 has 2 divisors, whose sum is σ = 34912101220014. Its totient is φ = 34912101220012.
The previous prime is 34912101219959. The next prime is 34912101220049. The reversal of 34912101220013 is 31002210121943.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20988740334409 + 13923360885604 = 4581347^2 + 3731402^2 .
It is a cyclic number.
It is not a de Polignac number, because 34912101220013 - 28 = 34912101219757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34912101220093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17456050610006 + 17456050610007.
It is an arithmetic number, because the mean of its divisors is an integer number (17456050610007).
Almost surely, 234912101220013 is an apocalyptic number.
It is an amenable number.
34912101220013 is a deficient number, since it is larger than the sum of its proper divisors (1).
34912101220013 is an equidigital number, since it uses as much as digits as its factorization.
34912101220013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 34912101220013 its reverse (31002210121943), we get a palindrome (65914311341956).
The spelling of 34912101220013 in words is "thirty-four trillion, nine hundred twelve billion, one hundred one million, two hundred twenty thousand, thirteen".
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