Base | Representation |
---|---|
bin | 1010001010111110001… |
… | …10011010000000101101 |
3 | 1020102002102002002110101 |
4 | 11011133012122000231 |
5 | 21211222343202101 |
6 | 424315201511101 |
7 | 34151430562636 |
oct | 5053706320055 |
9 | 1212072062411 |
10 | 349487865901 |
11 | 125242875429 |
12 | 57896942491 |
13 | 26c587584b5 |
14 | 12cb583c88d |
15 | 91570e0401 |
hex | 515f19a02d |
349487865901 has 2 divisors, whose sum is σ = 349487865902. Its totient is φ = 349487865900.
The previous prime is 349487865821. The next prime is 349487865907. The reversal of 349487865901 is 109568784943.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 307302813801 + 42185052100 = 554349^2 + 205390^2 .
It is a cyclic number.
It is not a de Polignac number, because 349487865901 - 225 = 349454311469 is a prime.
It is a super-3 number, since 3×3494878659013 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (349487865907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174743932950 + 174743932951.
It is an arithmetic number, because the mean of its divisors is an integer number (174743932951).
Almost surely, 2349487865901 is an apocalyptic number.
It is an amenable number.
349487865901 is a deficient number, since it is larger than the sum of its proper divisors (1).
349487865901 is an equidigital number, since it uses as much as digits as its factorization.
349487865901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52254720, while the sum is 64.
The spelling of 349487865901 in words is "three hundred forty-nine billion, four hundred eighty-seven million, eight hundred sixty-five thousand, nine hundred one".
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