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349734761317 is a prime number
BaseRepresentation
bin1010001011011011101…
…00001111001101100101
31020102201121122200022001
411011231310033031211
521212224044330232
6424355501405301
734160516264434
oct5055564171545
91212647580261
10349734761317
1112535a178627
1257945569831
1326c97951a66
1412cda54b11b
15916db0e6e7
hex516dd0f365

349734761317 has 2 divisors, whose sum is σ = 349734761318. Its totient is φ = 349734761316.

The previous prime is 349734761273. The next prime is 349734761381. The reversal of 349734761317 is 713167437943.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 330976993636 + 18757767681 = 575306^2 + 136959^2 .

It is an emirp because it is prime and its reverse (713167437943) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-349734761317 is a prime.

It is a super-4 number, since 4×3497347613174 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (349734761417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174867380658 + 174867380659.

It is an arithmetic number, because the mean of its divisors is an integer number (174867380659).

Almost surely, 2349734761317 is an apocalyptic number.

It is an amenable number.

349734761317 is a deficient number, since it is larger than the sum of its proper divisors (1).

349734761317 is an equidigital number, since it uses as much as digits as its factorization.

349734761317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8001504, while the sum is 55.

The spelling of 349734761317 in words is "three hundred forty-nine billion, seven hundred thirty-four million, seven hundred sixty-one thousand, three hundred seventeen".