Base | Representation |
---|---|
bin | 100111110001000001101001… |
… | …0101000110001101110000011 |
3 | 1200212111011221210022200120102 |
4 | 1033202003102220301232003 |
5 | 331321342023121203021 |
6 | 3235533152500233015 |
7 | 133451115664354106 |
oct | 11742032250615603 |
9 | 1625434853280512 |
10 | 349785670491011 |
11 | a14a82a710a1a7 |
12 | 3329298139b76b |
13 | 12023854b69611 |
14 | 6253a06bd073d |
15 | 2a68adc02900b |
hex | 13e20d2a31b83 |
349785670491011 has 2 divisors, whose sum is σ = 349785670491012. Its totient is φ = 349785670491010.
The previous prime is 349785670491001. The next prime is 349785670491013. The reversal of 349785670491011 is 110194076587943.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 349785670491011 - 26 = 349785670490947 is a prime.
It is a super-2 number, since 2×3497856704910112 (a number of 30 digits) contains 22 as substring.
Together with 349785670491013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (349785670491013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174892835245505 + 174892835245506.
It is an arithmetic number, because the mean of its divisors is an integer number (174892835245506).
Almost surely, 2349785670491011 is an apocalyptic number.
349785670491011 is a deficient number, since it is larger than the sum of its proper divisors (1).
349785670491011 is an equidigital number, since it uses as much as digits as its factorization.
349785670491011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45722880, while the sum is 65.
The spelling of 349785670491011 in words is "three hundred forty-nine trillion, seven hundred eighty-five billion, six hundred seventy million, four hundred ninety-one thousand, eleven".
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