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350000348713 is a prime number
BaseRepresentation
bin1010001011111011010…
…01010111111000101001
31020110102010101220201021
411011331221113320221
521213300042124323
6424442110052441
734200222606631
oct5057551277051
91213363356637
10350000348713
11125486088344
12579ba4aa121
132700a991272
1412d239236c1
1591870c205d
hex517da57e29

350000348713 has 2 divisors, whose sum is σ = 350000348714. Its totient is φ = 350000348712.

The previous prime is 350000348683. The next prime is 350000348743. The reversal of 350000348713 is 317843000053.

It is a balanced prime because it is at equal distance from previous prime (350000348683) and next prime (350000348743).

It can be written as a sum of positive squares in only one way, i.e., 260005148649 + 89995200064 = 509907^2 + 299992^2 .

It is a cyclic number.

It is not a de Polignac number, because 350000348713 - 25 = 350000348681 is a prime.

It is not a weakly prime, because it can be changed into another prime (350000348743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175000174356 + 175000174357.

It is an arithmetic number, because the mean of its divisors is an integer number (175000174357).

Almost surely, 2350000348713 is an apocalyptic number.

It is an amenable number.

350000348713 is a deficient number, since it is larger than the sum of its proper divisors (1).

350000348713 is an equidigital number, since it uses as much as digits as its factorization.

350000348713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 34.

Adding to 350000348713 its reverse (317843000053), we get a palindrome (667843348766).

The spelling of 350000348713 in words is "three hundred fifty billion, three hundred forty-eight thousand, seven hundred thirteen".