350010041 has 2 divisors, whose sum is σ = 350010042. Its totient is φ = 350010040.

The previous prime is 350010013. The next prime is 350010079. The reversal of 350010041 is 140010053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 303770041 + 46240000 = 17429^2 + 6800^2 .

It is an emirp because it is prime and its reverse (140010053) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-350010041 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 350009998 and 350010025.

It is not a weakly prime, because it can be changed into another prime (350010091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175005020 + 175005021.

It is an arithmetic number, because the mean of its divisors is an integer number (175005021).

Almost surely, 2^350010041 is an apocalyptic number.

It is an amenable number.

350010041 is a deficient number, since it is larger than the sum of its proper divisors (1).

350010041 is an equidigital number, since it uses as much as digits as its factorization.

350010041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 350010041 is about 18708.5552889580. Note that the first 3 decimals coincide. The cubic root of 350010041 is about 704.7366123731.

Adding to 350010041 its reverse (140010053), we get a palindrome (490020094).

The spelling of 350010041 in words is "three hundred fifty million, ten thousand, forty-one".