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350011200201 = 3138974646159
BaseRepresentation
bin1010001011111100100…
…10110001001011001001
31020110102212211020011020
411011332102301023021
521213310331401301
6424443134423053
734200414053625
oct5057622611311
91213385736136
10350011200201
1112549121a213
1257a02061a89
132700ccc0570
1412d2514a185
159188017436
hex517e4b12c9

350011200201 has 8 divisors (see below), whose sum is σ = 502580184960. Its totient is φ = 215391507792.

The previous prime is 350011200191. The next prime is 350011200239. The reversal of 350011200201 is 102002110053.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 350011200201 - 25 = 350011200169 is a prime.

It is a super-2 number, since 2×3500112002012 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (350011200701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4487323041 + ... + 4487323118.

It is an arithmetic number, because the mean of its divisors is an integer number (62822523120).

Almost surely, 2350011200201 is an apocalyptic number.

It is an amenable number.

350011200201 is a deficient number, since it is larger than the sum of its proper divisors (152568984759).

350011200201 is a wasteful number, since it uses less digits than its factorization.

350011200201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8974646175.

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 350011200201 its reverse (102002110053), we get a palindrome (452013310254).

The spelling of 350011200201 in words is "three hundred fifty billion, eleven million, two hundred thousand, two hundred one".

Divisors: 1 3 13 39 8974646159 26923938477 116670400067 350011200201