Base | Representation |
---|---|
bin | 100111110010101111001111… |
… | …0111000100110100010000110 |
3 | 1200220022200110002011010122111 |
4 | 1033211132132320212202012 |
5 | 331334221030002104132 |
6 | 3240233234513251234 |
7 | 133504120210323022 |
oct | 11745363670464206 |
9 | 1626280402133574 |
10 | 350021025425542 |
11 | a15890a0906a59 |
12 | 33310505263b1a |
13 | 1203cac1aa26a3 |
14 | 62611725b1382 |
15 | 2a6ecb428e647 |
hex | 13e579ee26886 |
350021025425542 has 4 divisors (see below), whose sum is σ = 525031538138316. Its totient is φ = 175010512712770.
The previous prime is 350021025425503. The next prime is 350021025425563. The reversal of 350021025425542 is 245524520120053.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 350021025425495 and 350021025425504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 87505256356384 + ... + 87505256356387.
It is an arithmetic number, because the mean of its divisors is an integer number (131257884534579).
Almost surely, 2350021025425542 is an apocalyptic number.
350021025425542 is a deficient number, since it is larger than the sum of its proper divisors (175010512712774).
350021025425542 is a wasteful number, since it uses less digits than its factorization.
350021025425542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 175010512712773.
The product of its (nonzero) digits is 480000, while the sum is 40.
Adding to 350021025425542 its reverse (245524520120053), we get a palindrome (595545545545595).
The spelling of 350021025425542 in words is "three hundred fifty trillion, twenty-one billion, twenty-five million, four hundred twenty-five thousand, five hundred forty-two".
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