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350040265243 is a prime number
BaseRepresentation
bin1010001100000000000…
…01101001001000011011
31020110111220111212220021
411012000001221020123
521213340301441433
6424450053411311
734201216106434
oct5060001511033
91213456455807
10350040265243
111254a6671209
1257a0b939b37
1327016028b06
1412d28d5448b
15918a85922d
hex518006921b

350040265243 has 2 divisors, whose sum is σ = 350040265244. Its totient is φ = 350040265242.

The previous prime is 350040265147. The next prime is 350040265259. The reversal of 350040265243 is 342562040053.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 350040265243 - 233 = 341450330651 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 350040265199 and 350040265208.

It is not a weakly prime, because it can be changed into another prime (350040265843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175020132621 + 175020132622.

It is an arithmetic number, because the mean of its divisors is an integer number (175020132622).

Almost surely, 2350040265243 is an apocalyptic number.

350040265243 is a deficient number, since it is larger than the sum of its proper divisors (1).

350040265243 is an equidigital number, since it uses as much as digits as its factorization.

350040265243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 34.

The spelling of 350040265243 in words is "three hundred fifty billion, forty million, two hundred sixty-five thousand, two hundred forty-three".