Base | Representation |
---|---|
bin | 100000100110011101… |
… | …011111100110100101 |
3 | 10100100120002110101221 |
4 | 200212131133212211 |
5 | 1033142240113242 |
6 | 24025302420341 |
7 | 2346312424552 |
oct | 404635374645 |
9 | 110316073357 |
10 | 35005004197 |
11 | 13933459839 |
12 | 694b1316b1 |
13 | 33bb286647 |
14 | 19a104da29 |
15 | d9d21d167 |
hex | 82675f9a5 |
35005004197 has 2 divisors, whose sum is σ = 35005004198. Its totient is φ = 35005004196.
The previous prime is 35005004171. The next prime is 35005004227. The reversal of 35005004197 is 79140050053.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34509006756 + 495997441 = 185766^2 + 22271^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35005004197 is a prime.
It is a super-2 number, since 2×350050041972 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35005004897) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17502502098 + 17502502099.
It is an arithmetic number, because the mean of its divisors is an integer number (17502502099).
Almost surely, 235005004197 is an apocalyptic number.
It is an amenable number.
35005004197 is a deficient number, since it is larger than the sum of its proper divisors (1).
35005004197 is an equidigital number, since it uses as much as digits as its factorization.
35005004197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18900, while the sum is 34.
The spelling of 35005004197 in words is "thirty-five billion, five million, four thousand, one hundred ninety-seven".
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