Base | Representation |
---|---|
bin | 1111111010110010101110… |
… | …11100010110101011111001 |
3 | 11120221111012000220122022112 |
4 | 13331121113130112223321 |
5 | 14042012130312410040 |
6 | 202241140523102105 |
7 | 10242026460633260 |
oct | 775312734265371 |
9 | 146844160818275 |
10 | 35005450513145 |
11 | 10176801251832 |
12 | 3b1435a671935 |
13 | 166bccc7ab508 |
14 | 8903b69875d7 |
15 | 40a88ac92365 |
hex | 1fd657716af9 |
35005450513145 has 64 divisors (see below), whose sum is σ = 48382424133120. Its totient is φ = 23817228982272.
The previous prime is 35005450513109. The next prime is 35005450513157. The reversal of 35005450513145 is 54131505450053.
It is a cyclic number.
It is not a de Polignac number, because 35005450513145 - 218 = 35005450251001 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2124495647 + ... + 2124512123.
It is an arithmetic number, because the mean of its divisors is an integer number (755975377080).
Almost surely, 235005450513145 is an apocalyptic number.
35005450513145 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
35005450513145 is a deficient number, since it is larger than the sum of its proper divisors (13376973619975).
35005450513145 is a wasteful number, since it uses less digits than its factorization.
35005450513145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17682.
The product of its (nonzero) digits is 450000, while the sum is 41.
Adding to 35005450513145 its reverse (54131505450053), we get a palindrome (89136955963198).
The spelling of 35005450513145 in words is "thirty-five trillion, five billion, four hundred fifty million, five hundred thirteen thousand, one hundred forty-five".
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