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350113 = 1918427
BaseRepresentation
bin1010101011110100001
3122210021011
41111132201
542200423
611300521
72655511
oct1253641
9583234
10350113
1121a055
1214a741
13c348a
1491841
156db0d
hex557a1

350113 has 4 divisors (see below), whose sum is σ = 368560. Its totient is φ = 331668.

The previous prime is 350111. The next prime is 350137. The reversal of 350113 is 311053.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311053 = 734261.

It is a cyclic number.

It is not a de Polignac number, because 350113 - 21 = 350111 is a prime.

It is a super-2 number, since 2×3501132 = 245158225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 350093 and 350102.

It is not an unprimeable number, because it can be changed into a prime (350111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9195 + ... + 9232.

It is an arithmetic number, because the mean of its divisors is an integer number (92140).

2350113 is an apocalyptic number.

It is an amenable number.

350113 is a deficient number, since it is larger than the sum of its proper divisors (18447).

350113 is a wasteful number, since it uses less digits than its factorization.

350113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18446.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 350113 is about 591.7034730336. The cubic root of 350113 is about 70.4805707404.

Adding to 350113 its reverse (311053), we get a palindrome (661166).

Subtracting from 350113 its reverse (311053), we obtain a triangular number (39060 = T279).

The spelling of 350113 in words is "three hundred fifty thousand, one hundred thirteen".

Divisors: 1 19 18427 350113