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35014235105413 is a prime number
BaseRepresentation
bin1111111011000011000110…
…00010111010100010000101
311120222022212020200011110201
413331201203002322202011
514042133123141333123
6202245152331250501
710242460246505404
oct775414302724205
9146868766604421
1035014235105413
111017a4a9996a43
123b15bb05a9a31
13166ca9c73b3c5
148909ab52963b
1540ac020be5ad
hex1fd8630ba885

35014235105413 has 2 divisors, whose sum is σ = 35014235105414. Its totient is φ = 35014235105412.

The previous prime is 35014235105363. The next prime is 35014235105483. The reversal of 35014235105413 is 31450153241053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17623858894084 + 17390376211329 = 4198078^2 + 4170177^2 .

It is a cyclic number.

It is not a de Polignac number, because 35014235105413 - 237 = 34876796151941 is a prime.

It is a super-2 number, since 2×350142351054132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35014235105483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17507117552706 + 17507117552707.

It is an arithmetic number, because the mean of its divisors is an integer number (17507117552707).

Almost surely, 235014235105413 is an apocalyptic number.

It is an amenable number.

35014235105413 is a deficient number, since it is larger than the sum of its proper divisors (1).

35014235105413 is an equidigital number, since it uses as much as digits as its factorization.

35014235105413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 35014235105413 its reverse (31450153241053), we get a palindrome (66464388346466).

The spelling of 35014235105413 in words is "thirty-five trillion, fourteen billion, two hundred thirty-five million, one hundred five thousand, four hundred thirteen".