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350153112013 = 1987176221999
BaseRepresentation
bin1010001100001101100…
…00000111100111001101
31020110210202212002120021
411012012300013213031
521214103144041023
6424505204222141
734204056225655
oct5060660074715
91213722762507
10350153112013
11125554337701
1257a4169a951
1327033519b53
1412d39d2b365
1591956ea35d
hex5186c079cd

350153112013 has 4 divisors (see below), whose sum is σ = 350329336000. Its totient is φ = 349976888028.

The previous prime is 350153112007. The next prime is 350153112041. The reversal of 350153112013 is 310211351053.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 350153112013 - 229 = 349616241101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (350153112053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88109013 + ... + 88112986.

It is an arithmetic number, because the mean of its divisors is an integer number (87582334000).

Almost surely, 2350153112013 is an apocalyptic number.

It is an amenable number.

350153112013 is a deficient number, since it is larger than the sum of its proper divisors (176223987).

350153112013 is a wasteful number, since it uses less digits than its factorization.

350153112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176223986.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 350153112013 its reverse (310211351053), we get a palindrome (660364463066).

The spelling of 350153112013 in words is "three hundred fifty billion, one hundred fifty-three million, one hundred twelve thousand, thirteen".

Divisors: 1 1987 176221999 350153112013