Base | Representation |
---|---|
bin | 1010001110000000110… |
… | …00100011100000010011 |
3 | 1020120022011020202211012 |
4 | 11013000120203200103 |
5 | 21223043210411311 |
6 | 425145144241135 |
7 | 34240036604153 |
oct | 5070030434023 |
9 | 1216264222735 |
10 | 351120013331 |
11 | 125a001039aa |
12 | 580714701ab |
13 | 271589387c9 |
14 | 12dcc500763 |
15 | 920053e78b |
hex | 51c0623813 |
351120013331 has 2 divisors, whose sum is σ = 351120013332. Its totient is φ = 351120013330.
The previous prime is 351120013313. The next prime is 351120013399. The reversal of 351120013331 is 133310021153.
Together with previous prime (351120013313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 351120013331 - 26 = 351120013267 is a prime.
It is a super-2 number, since 2×3511200133312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 351120013297 and 351120013306.
It is not a weakly prime, because it can be changed into another prime (351120043331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175560006665 + 175560006666.
It is an arithmetic number, because the mean of its divisors is an integer number (175560006666).
Almost surely, 2351120013331 is an apocalyptic number.
351120013331 is a deficient number, since it is larger than the sum of its proper divisors (1).
351120013331 is an equidigital number, since it uses as much as digits as its factorization.
351120013331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 351120013331 its reverse (133310021153), we get a palindrome (484430034484).
The spelling of 351120013331 in words is "three hundred fifty-one billion, one hundred twenty million, thirteen thousand, three hundred thirty-one".
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