Base | Representation |
---|---|
bin | 1010001110000001001… |
… | …10011001001010111111 |
3 | 1020120022102002002002011 |
4 | 11013000212121022333 |
5 | 21223100123003043 |
6 | 425145354112051 |
7 | 34240112463421 |
oct | 5070046311277 |
9 | 1216272062064 |
10 | 351123641023 |
11 | 125a021614a1 |
12 | 5807271b627 |
13 | 27159608a7c |
14 | 12dccba6811 |
15 | 9200a0959d |
hex | 51c09992bf |
351123641023 has 2 divisors, whose sum is σ = 351123641024. Its totient is φ = 351123641022.
The previous prime is 351123641017. The next prime is 351123641101. The reversal of 351123641023 is 320146321153.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 351123641023 - 225 = 351090086591 is a prime.
It is a super-2 number, since 2×3511236410232 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (351123641623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175561820511 + 175561820512.
It is an arithmetic number, because the mean of its divisors is an integer number (175561820512).
Almost surely, 2351123641023 is an apocalyptic number.
351123641023 is a deficient number, since it is larger than the sum of its proper divisors (1).
351123641023 is an equidigital number, since it uses as much as digits as its factorization.
351123641023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 351123641023 its reverse (320146321153), we get a palindrome (671269962176).
The spelling of 351123641023 in words is "three hundred fifty-one billion, one hundred twenty-three million, six hundred forty-one thousand, twenty-three".
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