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351142241411981 is a prime number
BaseRepresentation
bin100111111010111001010110…
…0100100001010001110001101
31201001021212111112211200102202
41033311302230210022032031
5332011103302300140411
63242452304015131245
7133651122041054315
oct11765625444121615
91631255445750382
10351142241411981
11a1980652021638
1233471876213b25
13120c1757156396
14629d537652445
152a8e03760383b
hex13f5cac90a38d

351142241411981 has 2 divisors, whose sum is σ = 351142241411982. Its totient is φ = 351142241411980.

The previous prime is 351142241411963. The next prime is 351142241412037. The reversal of 351142241411981 is 189114142241153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 322413123809956 + 28729117602025 = 17955866^2 + 5359955^2 .

It is a cyclic number.

It is not a de Polignac number, because 351142241411981 - 234 = 351125061542797 is a prime.

It is a super-2 number, since 2×3511422414119812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (351142241411911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175571120705990 + 175571120705991.

It is an arithmetic number, because the mean of its divisors is an integer number (175571120705991).

Almost surely, 2351142241411981 is an apocalyptic number.

It is an amenable number.

351142241411981 is a deficient number, since it is larger than the sum of its proper divisors (1).

351142241411981 is an equidigital number, since it uses as much as digits as its factorization.

351142241411981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 276480, while the sum is 47.

The spelling of 351142241411981 in words is "three hundred fifty-one trillion, one hundred forty-two billion, two hundred forty-one million, four hundred eleven thousand, nine hundred eighty-one".