Search a number
-
+
3511434345941 is a prime number
BaseRepresentation
bin110011000110010001110…
…010111111110111010101
3110102200121220012221112202
4303012101302333313111
5430012404143032231
611245044120254245
7511456421320124
oct63062162776725
913380556187482
103511434345941
111134211166555
12488658311385
131c6185880a42
14c1d50971abb
15615191115cb
hex33191cbfdd5

3511434345941 has 2 divisors, whose sum is σ = 3511434345942. Its totient is φ = 3511434345940.

The previous prime is 3511434345931. The next prime is 3511434345971. The reversal of 3511434345941 is 1495434341153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2025341691025 + 1486092654916 = 1423145^2 + 1219054^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3511434345941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3511434345911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1755717172970 + 1755717172971.

It is an arithmetic number, because the mean of its divisors is an integer number (1755717172971).

Almost surely, 23511434345941 is an apocalyptic number.

It is an amenable number.

3511434345941 is a deficient number, since it is larger than the sum of its proper divisors (1).

3511434345941 is an equidigital number, since it uses as much as digits as its factorization.

3511434345941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1555200, while the sum is 47.

The spelling of 3511434345941 in words is "three trillion, five hundred eleven billion, four hundred thirty-four million, three hundred forty-five thousand, nine hundred forty-one".