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35125000019 is a prime number
BaseRepresentation
bin100000101101100111…
…001111011101010011
310100122220212212201122
4200231213033131103
51033414000000034
624045230352455
72352300400604
oct405547173523
9110586785648
1035125000019
111399516843a
12698335b72b
13340a0ab6a5
1419b2d67dab
15da8a2262e
hex82d9cf753

35125000019 has 2 divisors, whose sum is σ = 35125000020. Its totient is φ = 35125000018.

The previous prime is 35124999961. The next prime is 35125000021. The reversal of 35125000019 is 91000052153.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 35125000019 - 212 = 35124995923 is a prime.

It is a super-2 number, since 2×351250000192 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 35125000021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (35125000319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17562500009 + 17562500010.

It is an arithmetic number, because the mean of its divisors is an integer number (17562500010).

Almost surely, 235125000019 is an apocalyptic number.

35125000019 is a deficient number, since it is larger than the sum of its proper divisors (1).

35125000019 is an equidigital number, since it uses as much as digits as its factorization.

35125000019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 26.

The spelling of 35125000019 in words is "thirty-five billion, one hundred twenty-five million, nineteen", and thus it is an aban number.