35130001 has 4 divisors (see below), whose sum is σ = 35259904. Its totient is φ = 35000100.

The previous prime is 35129929. The next prime is 35130013. The reversal of 35130001 is 10003153.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10003153 = 1609 ⋅6217.

It is a cyclic number.

It is not a de Polignac number, because 35130001 - 2⁷ = 35129873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35130061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64545 + ... + 65086.

It is an arithmetic number, because the mean of its divisors is an integer number (8814976).

Almost surely, 2^35130001 is an apocalyptic number.

It is an amenable number.

35130001 is a deficient number, since it is larger than the sum of its proper divisors (129903).

35130001 is a wasteful number, since it uses less digits than its factorization.

35130001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129902.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 35130001 is about 5927.0566894539. The cubic root of 35130001 is about 327.5111229056.

Adding to 35130001 its reverse (10003153), we get a palindrome (45133154).

The spelling of 35130001 in words is "thirty-five million, one hundred thirty thousand, one".