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35130451441 is a prime number
BaseRepresentation
bin100000101101111100…
…000010010111110001
310100200022010211200011
4200231330002113301
51033421343421231
624045543254521
72352364624141
oct405574022761
9110608124604
1035130451441
1113998251148
12698514a441
13340b269a97
1419b3986921
15da924c9b1
hex82df025f1

35130451441 has 2 divisors, whose sum is σ = 35130451442. Its totient is φ = 35130451440.

The previous prime is 35130451427. The next prime is 35130451469. The reversal of 35130451441 is 14415403153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22110500416 + 13019951025 = 148696^2 + 114105^2 .

It is a cyclic number.

It is not a de Polignac number, because 35130451441 - 27 = 35130451313 is a prime.

It is a super-4 number, since 4×351304514414 (a number of 43 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (35130451141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17565225720 + 17565225721.

It is an arithmetic number, because the mean of its divisors is an integer number (17565225721).

Almost surely, 235130451441 is an apocalyptic number.

It is an amenable number.

35130451441 is a deficient number, since it is larger than the sum of its proper divisors (1).

35130451441 is an equidigital number, since it uses as much as digits as its factorization.

35130451441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 35130451441 its reverse (14415403153), we get a palindrome (49545854594).

The spelling of 35130451441 in words is "thirty-five billion, one hundred thirty million, four hundred fifty-one thousand, four hundred forty-one".