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351342424243121 is a prime number
BaseRepresentation
bin100111111100010110100100…
…0011001000011101110110001
31201002000000012122011011002212
41033320231020121003232301
5332022343241101234441
63243124252000021505
7134001436542050603
oct11770551031035661
91632000178134085
10351342424243121
11a1a48538009553
12334a4623001895
13121075aa2cac5c
1462a90c7b27173
152a94351b3eeeb
hex13f8b48643bb1

351342424243121 has 2 divisors, whose sum is σ = 351342424243122. Its totient is φ = 351342424243120.

The previous prime is 351342424243117. The next prime is 351342424243123. The reversal of 351342424243121 is 121342424243153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 291101231532721 + 60241192710400 = 17061689^2 + 7761520^2 .

It is a cyclic number.

It is not a de Polignac number, because 351342424243121 - 22 = 351342424243117 is a prime.

Together with 351342424243123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (351342424243123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175671212121560 + 175671212121561.

It is an arithmetic number, because the mean of its divisors is an integer number (175671212121561).

Almost surely, 2351342424243121 is an apocalyptic number.

It is an amenable number.

351342424243121 is a deficient number, since it is larger than the sum of its proper divisors (1).

351342424243121 is an equidigital number, since it uses as much as digits as its factorization.

351342424243121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 552960, while the sum is 41.

Adding to 351342424243121 its reverse (121342424243153), we get a palindrome (472684848486274).

The spelling of 351342424243121 in words is "three hundred fifty-one trillion, three hundred forty-two billion, four hundred twenty-four million, two hundred forty-three thousand, one hundred twenty-one".