Base | Representation |
---|---|
bin | 100000101110100000… |
… | …011101101000000101 |
3 | 10100200222002222012011 |
4 | 200232200131220011 |
5 | 1033431320002021 |
6 | 24050524054221 |
7 | 2352542034232 |
oct | 405640355005 |
9 | 110628088164 |
10 | 35140000261 |
11 | 139a2683333 |
12 | 6988394371 |
13 | 3410231182 |
14 | 19b4d50789 |
15 | da9ed6de1 |
hex | 82e81da05 |
35140000261 has 2 divisors, whose sum is σ = 35140000262. Its totient is φ = 35140000260.
The previous prime is 35140000193. The next prime is 35140000271. The reversal of 35140000261 is 16200004153.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18837562500 + 16302437761 = 137250^2 + 127681^2 .
It is an emirp because it is prime and its reverse (16200004153) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35140000261 - 211 = 35139998213 is a prime.
It is a super-3 number, since 3×351400002613 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35140000271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17570000130 + 17570000131.
It is an arithmetic number, because the mean of its divisors is an integer number (17570000131).
Almost surely, 235140000261 is an apocalyptic number.
It is an amenable number.
35140000261 is a deficient number, since it is larger than the sum of its proper divisors (1).
35140000261 is an equidigital number, since it uses as much as digits as its factorization.
35140000261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 22.
The spelling of 35140000261 in words is "thirty-five billion, one hundred forty million, two hundred sixty-one", and thus it is an aban number.
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