Base | Representation |
---|---|
bin | 110011001110010111101… |
… | …110010001111111001111 |
3 | 110110112001110210020111211 |
4 | 303032113232101333033 |
5 | 430133203132113333 |
6 | 11253042243355251 |
7 | 512214642552235 |
oct | 63162756217717 |
9 | 13415043706454 |
10 | 3520123707343 |
11 | 1137970077371 |
12 | 48a282382b27 |
13 | 1c6c3bb79ac9 |
14 | c2536a04955 |
15 | 61876dcbecd |
hex | 33397b91fcf |
3520123707343 has 16 divisors (see below), whose sum is σ = 3677524952256. Its totient is φ = 3363087467520.
The previous prime is 3520123707283. The next prime is 3520123707379. The reversal of 3520123707343 is 3437073210253.
It is not a de Polignac number, because 3520123707343 - 221 = 3520121610191 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3520123707296 and 3520123707305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3520123707043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72172921 + ... + 72221677.
It is an arithmetic number, because the mean of its divisors is an integer number (229845309516).
Almost surely, 23520123707343 is an apocalyptic number.
3520123707343 is a deficient number, since it is larger than the sum of its proper divisors (157401244913).
3520123707343 is a wasteful number, since it uses less digits than its factorization.
3520123707343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52434.
The product of its (nonzero) digits is 317520, while the sum is 40.
Adding to 3520123707343 its reverse (3437073210253), we get a palindrome (6957196917596).
The spelling of 3520123707343 in words is "three trillion, five hundred twenty billion, one hundred twenty-three million, seven hundred seven thousand, three hundred forty-three".
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