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352055114314 = 2176027557157
BaseRepresentation
bin1010001111110000001…
…11101011101001001010
31020122201022210211012221
411013320013223221022
521232002102124224
6425422030524254
734302153045121
oct5077007535112
91218638724187
10352055114314
1112633aa30132
125829266668a
13272775a1bb7
141307a796ab8
1592576a16e4
hex51f81eba4a

352055114314 has 4 divisors (see below), whose sum is σ = 528082671474. Its totient is φ = 176027557156.

The previous prime is 352055114269. The next prime is 352055114381. The reversal of 352055114314 is 413411550253.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 413411550253 = 1331800888481.

It can be written as a sum of positive squares in only one way, i.e., 350908140625 + 1146973689 = 592375^2 + 33867^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 352055114314.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 88013778577 + ... + 88013778580.

Almost surely, 2352055114314 is an apocalyptic number.

352055114314 is a deficient number, since it is larger than the sum of its proper divisors (176027557160).

352055114314 is a wasteful number, since it uses less digits than its factorization.

352055114314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176027557159.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 352055114314 its reverse (413411550253), we get a palindrome (765466664567).

The spelling of 352055114314 in words is "three hundred fifty-two billion, fifty-five million, one hundred fourteen thousand, three hundred fourteen".

Divisors: 1 2 176027557157 352055114314