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352135004332081 is a prime number
BaseRepresentation
bin101000000010000111101000…
…1110110001010000000110001
31201011210202222220102100122111
41100010033101312022000301
5332123334442102111311
63244532330542005321
7134112625450463125
oct12004172166120061
91634722886370574
10352135004332081
11a2223686894263
12335b2158576841
131216425ac7b309
1462d55d4867585
152aa9c8d81ed21
hex14043d1d8a031

352135004332081 has 2 divisors, whose sum is σ = 352135004332082. Its totient is φ = 352135004332080.

The previous prime is 352135004332003. The next prime is 352135004332109. The reversal of 352135004332081 is 180233400531253.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 322681763589025 + 29453240743056 = 17963345^2 + 5427084^2 .

It is a cyclic number.

It is not a de Polignac number, because 352135004332081 - 27 = 352135004331953 is a prime.

It is a super-2 number, since 2×3521350043320812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (352135004336081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176067502166040 + 176067502166041.

It is an arithmetic number, because the mean of its divisors is an integer number (176067502166041).

Almost surely, 2352135004332081 is an apocalyptic number.

It is an amenable number.

352135004332081 is a deficient number, since it is larger than the sum of its proper divisors (1).

352135004332081 is an equidigital number, since it uses as much as digits as its factorization.

352135004332081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 352135004332081 in words is "three hundred fifty-two trillion, one hundred thirty-five billion, four million, three hundred thirty-two thousand, eighty-one".