Base | Representation |
---|---|
bin | 1010001111111010011… |
… | …01111100001111011001 |
3 | 1020122221021202001002220 |
4 | 11013331031330033121 |
5 | 21232141001004431 |
6 | 425434324014253 |
7 | 34304242030554 |
oct | 5077515741731 |
9 | 1218837661086 |
10 | 352140641241 |
11 | 126384236844 |
12 | 582b7231389 |
13 | 2728c218b4c |
14 | 13087c9b69b |
15 | 925ee47b96 |
hex | 51fd37c3d9 |
352140641241 has 4 divisors (see below), whose sum is σ = 469520854992. Its totient is φ = 234760427492.
The previous prime is 352140641159. The next prime is 352140641263. The reversal of 352140641241 is 142146041253.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142146041253 = 3 ⋅47382013751.
It is a cyclic number.
It is not a de Polignac number, because 352140641241 - 219 = 352140116953 is a prime.
It is not an unprimeable number, because it can be changed into a prime (352140641441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58690106871 + ... + 58690106876.
It is an arithmetic number, because the mean of its divisors is an integer number (117380213748).
Almost surely, 2352140641241 is an apocalyptic number.
It is an amenable number.
352140641241 is a deficient number, since it is larger than the sum of its proper divisors (117380213751).
352140641241 is a wasteful number, since it uses less digits than its factorization.
352140641241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117380213750.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 352140641241 its reverse (142146041253), we get a palindrome (494286682494).
The spelling of 352140641241 in words is "three hundred fifty-two billion, one hundred forty million, six hundred forty-one thousand, two hundred forty-one".
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